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2c^2-15c=-25
We move all terms to the left:
2c^2-15c-(-25)=0
We add all the numbers together, and all the variables
2c^2-15c+25=0
a = 2; b = -15; c = +25;
Δ = b2-4ac
Δ = -152-4·2·25
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-5}{2*2}=\frac{10}{4} =2+1/2 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+5}{2*2}=\frac{20}{4} =5 $
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